36x^2+60x-24=0

Solution for 36x^2+60x-24=0 equation:

36x^2+60x-24=0

a = 36; b = 60; c = -24;
Δ = b2-4ac
Δ = 602-4·36·(-24)
Δ = 7056
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{7056}=84$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-84}{2*36}=\frac{-144}{72}
=-2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+84}{2*36}=\frac{24}{72}
=1/3
$